ማባዛት እንደ ተመሳሳይ ቃላት ድምር ሊወከል የሚችል የሂሳብ አሠራር ነው።

ይዘት

አጠቃላይ የማባዛት መርህ

ለምሳሌ, ሀ ⋅ ለ (እንደ “ጊዜ ለ” አንብብ) ማለት ቃላቶቹን ጠቅለል አድርገን እንገልጻለን። a, ቁጥሩ እኩል ነው b. የማባዛት ውጤት ምርት ይባላል።

የማባዛት ሰንጠረዥን በፍጥነት እና በቀላሉ እንዴት መማር እንደሚቻል

ምሳሌዎች

  • 2 ⋅ 6 = 2 + 2 + 2 + 2 + 2 + 2 = 12

    (ስድስት ጊዜ ሁለት)

  • 5 ⋅ 4 = 5 + 5 + 5 + 5 = 20

    (አራት ጊዜ አምስት)

  • 3 ⋅ 8 = 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 = 24

    (ስምንት ጊዜ ሶስት)

እንደምናውቀው, የምክንያቶች ቦታዎች ከ permutation, ምርቱ አይለወጥም. ከላይ ለተጠቀሱት ምሳሌዎች የሚከተለው ይሆናል-

  • 6 ⋅ 2 = 6 + 6 = 12

    (ሁለት ጊዜ ስድስት)

  • 4 ⋅ 5 = 4 + 4 + 4 + 4 + 4 = 20

    (አምስት ጊዜ አራት)

  • 8 ⋅ 3 = 8 + 8 + 8 = 24

    (ሦስት ጊዜ ስምንት)

ተግባራዊ ጥቅሞች

ለማባዛት ምስጋና ይግባውና የጠቅላላውን ተመሳሳይ አይነት እቃዎች ብዛት በከፍተኛ ሁኔታ መቀነስ ይችላሉ, ወዘተ ለምሳሌ, 7 ጥቅሎች ካሉን, እያንዳንዳቸው 5 እስክሪብቶች ያሉት ከሆነ, እነዚህን በማባዛት የጠቅላላው እስክሪብቶች ብዛት ይገኛል. ሁለት ቁጥሮች:

5 ⋅ 7 = 5 + 5 + 5 + 5 + 5 + 5 + 5 = 35

(አምስት እስክሪብቶች ሰባት ጊዜ)

በ 0 ማባዛት

ውጤቱ ሁልጊዜ ዜሮ ነው.

  • 0፣0 ⋅ 0 = XNUMX፣XNUMX
  • 1 ⋅ 0 = 0 ⋅ 1 = 0
  • 2 ⋅ 0 = 0 ⋅ 2 = 0 + 0 = 0
  • 3 ⋅ 0 = 0 ⋅ 3 = 0 + 0 + 0 = 0
  • 4 ⋅ 0 = 0 ⋅ 4 = 0 + 0 + 0 + 0 = 0
  • 5 ⋅ 0 = 0 ⋅ 5 = 0 + 0 + 0 + 0 + 0 = 0
  • 6 ⋅ 0 = 0 ⋅ 6 = 0 + 0 + 0 + 0 + 0 + 0 = 0
  • 7 ⋅ 0 = 0 ⋅ 7 = 0 + 0 + 0 + 0 + 0 + 0 + 0 = 0
  • 8 ⋅ 0 = 0 ⋅ 8 = 0 + 0 + 0 + 0 + 0 + 0 + 0 + 0 = 0
  • 9 ⋅ 0 = 0 ⋅ 9 = 0 + 0 + 0 + 0 + 0 + 0 + 0 + 0 + 0 = 0
  • 10 ⋅ 0 = 0 ⋅ 10 = 0 + 0 + 0 + 0 + 0 + 0 + 0 + 0 + 0 + 0 = 0

በ 1 ማባዛት

ምርቱ ከአንድ ሌላ ማባዣ ጋር እኩል ነው.

  • 1፣1 ⋅ 1 = XNUMX፣XNUMX
  • 2 ⋅ 1 = 2 ⋅ 1 = 2
  • 3 ⋅ 1 = 3 ⋅ 1 = 3
  • 4 ⋅ 1 = 4 ⋅ 1 = 4
  • 5 ⋅ 1 = 5 ⋅ 1 = 5
  • 6 ⋅ 1 = 6 ⋅ 1 = 6
  • 7 ⋅ 1 = 7 ⋅ 1 = 7
  • 8 ⋅ 1 = 8 ⋅ 1 = 8
  • 9 ⋅ 1 = 9 ⋅ 1 = 9
  • 10 ⋅ 1 = 10 ⋅ 1 = 10

በ 2 ማባዛት

የመጀመሪያውን ሁኔታ ወደ ራሱ ያክሉ።

  • 1 ⋅ 2 = 1 + 1 = 2
  • 2 ⋅ 2 = 2 + 2 = 4
  • 3 ⋅ 2 = 3 + 3 = 6
  • 4 ⋅ 2 = 4 + 4 = 8
  • 5 ⋅ 2 = 5 + 5 = 10
  • 6 ⋅ 2 = 6 + 6 = 12
  • 7 ⋅ 2 = 7 + 7 = 14
  • 8 ⋅ 2 = 8 + 8 = 16
  • 9 ⋅ 2 = 9 + 9 = 18
  • 10 ⋅ 2 = 10 + 10 = 20

በ 3 ማባዛት

የመጀመሪያውን ደረጃ በ 2 እናባዛለን, ከዚያም ወደ ውጤቱ እንጨምራለን.

  • 1 ⋅ 3 = (1⋅ 2) + 1 = 2 + 1 = 3
  • 2 ⋅ 3 = (2⋅ 2) + 2 = 4 + 2 = 6
  • 3 ⋅ 3 = (3⋅ 2) + 3 = 6 + 3 = 9
  • 4 ⋅ 3 = (4⋅ 2) + 4 = 8 + 4 = 12
  • 5 ⋅ 3 = (5⋅ 2) + 5 = 10 + 5 = 15
  • 6 ⋅ 3 = (6⋅ 2) + 6 = 12 + 6 = 18
  • 7 ⋅ 3 = (7⋅ 2) + 7 = 14 + 7 = 21
  • 8 ⋅ 3 = (8⋅ 2) + 8 = 16 + 8 = 24
  • 9 ⋅ 3 = (9⋅ 2) + 9 = 18 + 9 = 27
  • 10 ⋅ 3 = (10⋅ 2) + 10 = 20 + 10 = 30

በ 4 ማባዛት

በእጥፍ የመጀመሪያ ደረጃ ላይ ተመሳሳይ መጠን እንጨምራለን.

  • 1 ⋅ 4 = (1 ⋅ 2) + (1 ⋅ 2) = 2 + 2 = 4
  • 2 ⋅ 4 = (2 ⋅ 2) + (2 ⋅ 2) = 4 + 4 = 8
  • 3 ⋅ 4 = (3 ⋅ 2) + (3 ⋅ 2) = 6 + 6 = 12
  • 4 ⋅ 4 = (4 ⋅ 2) + (4 ⋅ 2) = 8 + 8 = 16
  • 5 ⋅ 4 = (5 ⋅ 2) + (5 ⋅ 2) = 10 + 10 = 20
  • 6 ⋅ 4 = (6 ⋅ 2) + (6 ⋅ 2) = 12 + 12 = 24
  • 7 ⋅ 4 = (7 ⋅ 2) + (7 ⋅ 2) = 14 + 14 = 28
  • 8 ⋅ 4 = (8 ⋅ 2) + (8 ⋅ 2) = 16 + 16 = 32
  • 9 ⋅ 4 = (9 ⋅ 2) + (9 ⋅ 2) = 18 + 18 = 36
  • 10 ⋅ 4 = (10 ⋅ 2) + (10 ⋅ 2) = 20 + 20 = 40

በ 5 ማባዛት

ሌላው ማባዣ እኩል የሆነ ቁጥር ከሆነ ውጤቱ በዜሮ፣ እንግዳ ከሆነ፣ በቁጥር 5 ያበቃል።

  • 1 ⋅ 5 = 5 ⋅ 1 = 5
  • 2 ⋅ 5 = 5 ⋅ 2 = 5 + 5 = 10
  • 3 ⋅ 5 = 5 ⋅ 3 = (5 ⋅ 2) + 5 = 15
  • 4 ⋅ 5 = 5 ⋅ 4 = (5 ⋅ 2) + (5 ⋅ 2) = 20
  • 5 ⋅ 5 = 5 + 5 + 5 + 5 + 5 = 25
  • 6 ⋅ 5 = 5 ⋅ 6 = (5 ⋅ 5) + 5 = 30
  • 7 ⋅ 5 = 5 ⋅ 7 = 5 + 5 + 5 + 5 + 5 + 5 + 5 = 35
  • 8 ⋅ 5 = 5 ⋅ 8 = (5 ⋅ 4) + (5 ⋅ 4) = 40
  • 9 ⋅ 5 = 5 ⋅ 9 = (5 ⋅ 10) - 5 = 45
  • 10 ⋅ 5 = 5 ⋅ 10 = 50

በ 6 ማባዛት

የመጀመሪያውን ደረጃ በ 5 እናባዛለን, ከዚያም ውጤቱን በእሱ ላይ እንጨምራለን.

  • 1 ⋅ 6 = (1⋅ 5) + 1 = 5 + 1 = 6
  • 2 ⋅ 6 = (2⋅ 5) + 2 = 10 + 2 = 12
  • 3 ⋅ 6 = (3⋅ 5) + 3 = 15 + 3 = 18
  • 4 ⋅ 6 = (4⋅ 5) + 4 = 20 + 4 = 24
  • 5 ⋅ 6 = (5⋅ 5) + 5 = 25 + 5 = 30
  • 6 ⋅ 6 = (6⋅ 5) + 6 = 30 + 6 = 36
  • 7 ⋅ 6 = (7⋅ 5) + 7 = 35 + 7 = 42
  • 8 ⋅ 6 = (8⋅ 5) + 8 = 40 + 8 = 48
  • 9 ⋅ 6 = (9⋅ 5) + 9 = 45 + 9 = 54
  • 10 ⋅ 6 = (10⋅ 5) + 10 = 50 + 10 = 60

በ 7 ማባዛት

በ 7 ለማባዛት ምንም ቀለል ያለ ስልተ-ቀመር የለም, ስለዚህ ለሌሎች ሁኔታዎች ተፈፃሚነት ያላቸውን ዘዴዎች እንጠቀማለን.

  • 1 ⋅ 7 = 7 ⋅ 1 = 7
  • 2 ⋅ 7 = 7 ⋅ 2 = 7 + 7 = 14
  • 3 ⋅ 7 = 7 ⋅ 3 = (7 ⋅ 2) + 7 = 21
  • 4 ⋅ 7 = 7 ⋅ 4 = (7 ⋅ 2) + (7 ⋅ 2) = 28
  • 5 ⋅ 7 = 7 ⋅ 5 = 7 + 7 + 7 + 7 + 7 = 35
  • 6 ⋅ 7 = 7 ⋅ 6 = (7 ⋅ 5) + 7 = 42
  • 7 ⋅ 7 = 7 + 7 + 7 + 7 + 7 + 7 + 7 = 49
  • 8 ⋅ 7 = 7 ⋅ 8 = (7 ⋅ 4) + (7 ⋅ 4) = 56
  • 9 ⋅ 7 = 7 ⋅ 9 = (7 ⋅ 10) - 7 = 63
  • 10፣7 ⋅ 70 = XNUMX፣XNUMX

በ 8 ማባዛት

የመጀመሪያውን ደረጃ በ 4 እናባዛለን, ከዚያም ወደ ውጤቱ ተመሳሳይ መጠን እንጨምራለን.

  • 1 ⋅ 8 = (1 ⋅ 4) + (1 ⋅ 4) = 8
  • 2 ⋅ 8 = (2 ⋅ 4) + (2 ⋅ 4) = 16
  • 3 ⋅ 8 = (3 ⋅ 4) + (3 ⋅ 4) = 24
  • 4 ⋅ 8 = (4 ⋅ 4) + (4 ⋅ 4) = 32
  • 5 ⋅ 8 = (5 ⋅ 4) + (5 ⋅ 4) = 40
  • 6 ⋅ 8 = (6 ⋅ 4) + (6 ⋅ 4) = 48
  • 7 ⋅ 8 = (7 ⋅ 4) + (7 ⋅ 4) = 56
  • 8 ⋅ 8 = (8 ⋅ 4) + (8 ⋅ 4) = 64
  • 9 ⋅ 8 = (9 ⋅ 4) + (9 ⋅ 4) = 72
  • 10 ⋅ 8 = (10 ⋅ 4) + (10 ⋅ 4) = 80

በ 9 ማባዛት

የመጀመሪያውን ደረጃ በ 10 እናባዛለን, እና ከተገኘው ውጤት እንቀንሳለን.

  • 1 ⋅ 9 = (1⋅ 10) - 1 = 10 - 1 = 9
  • 2 ⋅ 9 = (2⋅ 10) - 2 = 20 - 2 = 18
  • 3 ⋅ 9 = (3⋅ 10) - 3 = 30 - 3 = 27
  • 4 ⋅ 9 = (4⋅ 10) - 4 = 40 - 4 = 36
  • 5 ⋅ 9 = (5⋅ 10) - 5 = 50 - 5 = 45
  • 6 ⋅ 9 = (6⋅ 10) - 6 = 60 - 6 = 54
  • 7 ⋅ 9 = (7⋅ 10) - 7 = 70 - 7 = 63
  • 8 ⋅ 9 = (8⋅ 10) - 8 = 80 - 8 = 72
  • 9 ⋅ 9 = (9⋅ 10) - 9 = 90 - 9 = 81
  • 10 ⋅ 9 = (10⋅ 10) - 10 = 100 - 10 = 90

በ 10 ማባዛት

በሌላኛው ማባዣ መጨረሻ ላይ ዜሮን ጨምር።

  • 1 ⋅ 10 = 10 ⋅ 1 = 10
  • 2 ⋅ 10 = 10 ⋅ 2 = 20
  • 3 ⋅ 10 = 10 ⋅ 3 = 30
  • 4 ⋅ 10 = 10 ⋅ 4 = 40
  • 5 ⋅ 10 = 10 ⋅ 5 = 50
  • 6 ⋅ 10 = 10 ⋅ 6 = 60
  • 7 ⋅ 10 = 10 ⋅ 7 = 70
  • 8 ⋅ 10 = 10 ⋅ 8 = 80
  • 9 ⋅ 10 = 10 ⋅ 9 = 90
  • 10 ⋅ 10 = 10 ⋅ 10 = 100

መልስ ይስጡ